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bantu jawab kakbesok dikumpulkanyang jawabannya ngawur cuma mau poin doang

Berikut ini adalah pertanyaan dari ouzanhafizh pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Bantu jawab kak
besok dikumpulkan

yang jawabannya ngawur cuma mau poin doang = report​
bantu jawab kakbesok dikumpulkanyang jawabannya ngawur cuma mau poin doang = report​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Penjelasan dengan langkah-langkah:

NOMOR 8

____________________________

\tt {}L = \frac{135}{360} \times \pi \times r \times 2 \\ \\ \tt{} = \frac{135}{360} \times \frac{22}{7} \times 7 \times 2 \\ \\ \tt{} = \red 1 \red6 \red, \red5 \: \red c \red m

____________________________

NOMOR 9

\tt{}L = \frac{45}{360} \times \pi \times r \\ \\ \tt{} = \frac{1}{8} \times \frac{22}{7} \times 14 {}^{2} \\ \\ \tt{} = \frac{4312}{56} \\ \\ \tt = \red 7 \red 7 \: \red c \red m²

____________________________

NOMOR 10

\tt{}22 = \frac{120}{360} \times 2\pi \: r \\ \\ \tt{}11= \frac{1}{3} \times \frac{22}{7} \times r \\ \\ \tt{}21 = 2 \: r \\ \\ \tt{}r = \frac{21}{2} \\ \\ \tt{}r = \red 1 \red 0 \red , \red 5 \: \red c \red m

____________________________

NOMOR 11

\tt{}luar = \sqrt{(26 {}^{2} - (18 - 8 ) {}^{2} } \\ \\ \tt{} = \sqrt{676 - 100} \\ \\ \tt{} = \sqrt{576} \\ \\ \tt{} = \red 2 \red 4 \: \red c \red m

____________________________

NOMOR 12

\tt{}24 = \sqrt{p {}^{2} - (8 - 1) {}^{2} } \\ \\ \tt{}24 {}^{2} = p {}^{2} - 7 {}^{2} \\ \\ \tt{}576 = p {}^{2} - 49 \\ \\ \tt{}p {}^{2} = 576 + 49 \\ \\ \tt{}p {}^{2} = \sqrt{625} \\ \\ \tt{}p = \red 2 \red 5 \: \red c \red m

\underline{\colorbox{blac}{\colorbox{pink}{\color{black}{ \tt \tiny Nananadya}}}}

Penjelasan dengan langkah-langkah:NOMOR 8____________________________[tex]\tt {}L = \frac{135}{360} \times \pi \times r \times 2 \\ \\ \tt{} = \frac{135}{360} \times \frac{22}{7} \times 7 \times 2 \\ \\ \tt{} = \red 1 \red6 \red, \red5 \: \red c \red m[/tex]____________________________NOMOR 9[tex] \tt{}L = \frac{45}{360} \times \pi \times r \\ \\ \tt{} = \frac{1}{8} \times \frac{22}{7} \times 14 {}^{2} \\ \\ \tt{} = \frac{4312}{56} \\ \\ \tt = \red 7 \red 7 \: \red c \red m²[/tex]____________________________NOMOR 10[tex] \tt{}22 = \frac{120}{360} \times 2\pi \: r \\ \\ \tt{}11= \frac{1}{3} \times \frac{22}{7} \times r \\ \\ \tt{}21 = 2 \: r \\ \\ \tt{}r = \frac{21}{2} \\ \\ \tt{}r = \red 1 \red 0 \red , \red 5 \: \red c \red m[/tex]____________________________ NOMOR 11[tex] \tt{}luar = \sqrt{(26 {}^{2} - (18 - 8 ) {}^{2} } \\ \\ \tt{} = \sqrt{676 - 100} \\ \\ \tt{} = \sqrt{576} \\ \\ \tt{} = \red 2 \red 4 \: \red c \red m[/tex]____________________________NOMOR 12[tex] \tt{}24 = \sqrt{p {}^{2} - (8 - 1) {}^{2} } \\ \\ \tt{}24 {}^{2} = p {}^{2} - 7 {}^{2} \\ \\ \tt{}576 = p {}^{2} - 49 \\ \\ \tt{}p {}^{2} = 576 + 49 \\ \\ \tt{}p {}^{2} = \sqrt{625} \\ \\ \tt{}p = \red 2 \red 5 \: \red c \red m[/tex][tex]\underline{\colorbox{blac}{\colorbox{pink}{\color{black}{ \tt \tiny Nananadya}}}}[/tex]Penjelasan dengan langkah-langkah:NOMOR 8____________________________[tex]\tt {}L = \frac{135}{360} \times \pi \times r \times 2 \\ \\ \tt{} = \frac{135}{360} \times \frac{22}{7} \times 7 \times 2 \\ \\ \tt{} = \red 1 \red6 \red, \red5 \: \red c \red m[/tex]____________________________NOMOR 9[tex] \tt{}L = \frac{45}{360} \times \pi \times r \\ \\ \tt{} = \frac{1}{8} \times \frac{22}{7} \times 14 {}^{2} \\ \\ \tt{} = \frac{4312}{56} \\ \\ \tt = \red 7 \red 7 \: \red c \red m²[/tex]____________________________NOMOR 10[tex] \tt{}22 = \frac{120}{360} \times 2\pi \: r \\ \\ \tt{}11= \frac{1}{3} \times \frac{22}{7} \times r \\ \\ \tt{}21 = 2 \: r \\ \\ \tt{}r = \frac{21}{2} \\ \\ \tt{}r = \red 1 \red 0 \red , \red 5 \: \red c \red m[/tex]____________________________ NOMOR 11[tex] \tt{}luar = \sqrt{(26 {}^{2} - (18 - 8 ) {}^{2} } \\ \\ \tt{} = \sqrt{676 - 100} \\ \\ \tt{} = \sqrt{576} \\ \\ \tt{} = \red 2 \red 4 \: \red c \red m[/tex]____________________________NOMOR 12[tex] \tt{}24 = \sqrt{p {}^{2} - (8 - 1) {}^{2} } \\ \\ \tt{}24 {}^{2} = p {}^{2} - 7 {}^{2} \\ \\ \tt{}576 = p {}^{2} - 49 \\ \\ \tt{}p {}^{2} = 576 + 49 \\ \\ \tt{}p {}^{2} = \sqrt{625} \\ \\ \tt{}p = \red 2 \red 5 \: \red c \red m[/tex][tex]\underline{\colorbox{blac}{\colorbox{pink}{\color{black}{ \tt \tiny Nananadya}}}}[/tex]Penjelasan dengan langkah-langkah:NOMOR 8____________________________[tex]\tt {}L = \frac{135}{360} \times \pi \times r \times 2 \\ \\ \tt{} = \frac{135}{360} \times \frac{22}{7} \times 7 \times 2 \\ \\ \tt{} = \red 1 \red6 \red, \red5 \: \red c \red m[/tex]____________________________NOMOR 9[tex] \tt{}L = \frac{45}{360} \times \pi \times r \\ \\ \tt{} = \frac{1}{8} \times \frac{22}{7} \times 14 {}^{2} \\ \\ \tt{} = \frac{4312}{56} \\ \\ \tt = \red 7 \red 7 \: \red c \red m²[/tex]____________________________NOMOR 10[tex] \tt{}22 = \frac{120}{360} \times 2\pi \: r \\ \\ \tt{}11= \frac{1}{3} \times \frac{22}{7} \times r \\ \\ \tt{}21 = 2 \: r \\ \\ \tt{}r = \frac{21}{2} \\ \\ \tt{}r = \red 1 \red 0 \red , \red 5 \: \red c \red m[/tex]____________________________ NOMOR 11[tex] \tt{}luar = \sqrt{(26 {}^{2} - (18 - 8 ) {}^{2} } \\ \\ \tt{} = \sqrt{676 - 100} \\ \\ \tt{} = \sqrt{576} \\ \\ \tt{} = \red 2 \red 4 \: \red c \red m[/tex]____________________________NOMOR 12[tex] \tt{}24 = \sqrt{p {}^{2} - (8 - 1) {}^{2} } \\ \\ \tt{}24 {}^{2} = p {}^{2} - 7 {}^{2} \\ \\ \tt{}576 = p {}^{2} - 49 \\ \\ \tt{}p {}^{2} = 576 + 49 \\ \\ \tt{}p {}^{2} = \sqrt{625} \\ \\ \tt{}p = \red 2 \red 5 \: \red c \red m[/tex][tex]\underline{\colorbox{blac}{\colorbox{pink}{\color{black}{ \tt \tiny Nananadya}}}}[/tex]

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Last Update: Tue, 06 Sep 22
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