Jawaban:

lihat pembahasan

Penjelasan:

diketahui:

• massa, m11 = 1 kg

• massa, m12 = 2 kg

• massa, m22 = 2 kg

• μk = 0 → lantai licin

ditanya:

perbandingan T1/T2

dijawab:

ΣF11 = 0

T11 = m . a

T11 = a

ΣF12 = m . a

w12 - T12 = m . a

2 . 10 - T12 = 2a

T12 = 20 - 2a

ΣF22 = m . a

T12 + w22 - T22 = m . a

20 - 2a + 2 . 10 - T22 = 2a

T22 = 40 - 4a

T12 = T22

a = 40 - 4a

5a = 40

a = 8 m/s²

→ T12 = a

T12 = 8 N

→ T22 = 40 - 4a

T22 = 40 - 4(8)

T22 = 40 - 32

T22 = 8 N

sehingga, perbandingan T1/T2 adalah:

• T1/T2 = 8 N / 8 N = 1 (A)

semoga membantu ya. cmiiw :)