Berikut ini adalah pertanyaan dari hafizah2312 pada mata pelajaran Matematika untuk jenjang Sekolah Dasar
Q1.) 99³ × 99³ ÷ 99⁴ = ...?
2.) 8³ × 3³ = ...?
_ _ _ _ _ _ _ _ _ _ _ _ _
→ No Calcu
![Q1.) 99³ × 99³ ÷ 99⁴ = ...?2.) 8³ × 3³ = ...?_ _ _ _ _ _ _ _ _ _ _ _ _→ No Calcu](https://id-static.z-dn.net/files/d71/bdf749c126632115374067f3b1d1fd79.jpg)
2.) 8³ × 3³ = ...?
_ _ _ _ _ _ _ _ _ _ _ _ _
→ No Calcu
![Q1.) 99³ × 99³ ÷ 99⁴ = ...?2.) 8³ × 3³ = ...?_ _ _ _ _ _ _ _ _ _ _ _ _→ No Calcu](https://id-static.z-dn.net/files/d71/bdf749c126632115374067f3b1d1fd79.jpg)
Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
1.) 99³ × 99³ ÷ 99⁴ =
= 99^( 3 + 3 - 4 )
= 99^( 6 - 4 )
= 99²
= 99 × 99
= 9.801
-------------
2.) 8³ × 3³ =
= ( 8 × 8 × 8 ) × ( 3 × 3 × 3 )
= ( 64 × 8 ) × ( 9 × 3 )
= 512 × 27
= 13.824
![Jawaban:operasi perpangkatan[tex]a {}^{m} \times a {}^{n} = a {}^{m + n} \\ a {}^{m} \div a {}^{n} = a {}^{m - n} \\ (a {}^{m} ) {}^{n} = a {}^{m \times n} \\ (a \times b) {}^{m} = a {}^{m} \times {}^{m} \\ ( \frac{a}{b} ) {}^{m} = \frac{a {}^{m} }{b {}^{m} } \\ a {}^{0} = 1 \\ a {}^{ - m} = \frac{1}{a {}^{m} } [/tex][tex]1.[/tex][tex]99 {}^{3} \times 99 {}^{3} \div 99 {}^{4} = [/tex][tex] = 99 {}^{3 + 3 - 4} [/tex][tex] = 99 {}^{6 - 4} [/tex][tex] = 99 {}^{2} [/tex][tex] = 99 \times 99[/tex][tex] = 9.801[/tex]==========================[tex]2.[/tex][tex]8 {}^{3} \times 3 {}^{3} = [/tex][tex] = (8 \times 8) \times 8 \times (3 \times 3 ) \times 3[/tex][tex] =( 64 \times 8) \times (9 \times 3)[/tex][tex] = 512 \times 27[/tex][tex] = 13.824[/tex]](https://id-static.z-dn.net/files/de7/047e0b40cd5d87859b0cc500f30da84b.jpg)
![Jawaban:operasi perpangkatan[tex]a {}^{m} \times a {}^{n} = a {}^{m + n} \\ a {}^{m} \div a {}^{n} = a {}^{m - n} \\ (a {}^{m} ) {}^{n} = a {}^{m \times n} \\ (a \times b) {}^{m} = a {}^{m} \times {}^{m} \\ ( \frac{a}{b} ) {}^{m} = \frac{a {}^{m} }{b {}^{m} } \\ a {}^{0} = 1 \\ a {}^{ - m} = \frac{1}{a {}^{m} } [/tex][tex]1.[/tex][tex]99 {}^{3} \times 99 {}^{3} \div 99 {}^{4} = [/tex][tex] = 99 {}^{3 + 3 - 4} [/tex][tex] = 99 {}^{6 - 4} [/tex][tex] = 99 {}^{2} [/tex][tex] = 99 \times 99[/tex][tex] = 9.801[/tex]==========================[tex]2.[/tex][tex]8 {}^{3} \times 3 {}^{3} = [/tex][tex] = (8 \times 8) \times 8 \times (3 \times 3 ) \times 3[/tex][tex] =( 64 \times 8) \times (9 \times 3)[/tex][tex] = 512 \times 27[/tex][tex] = 13.824[/tex]](https://id-static.z-dn.net/files/da6/8d5a4497561926f2798f4d14a48ac8b1.jpg)
![Jawaban:operasi perpangkatan[tex]a {}^{m} \times a {}^{n} = a {}^{m + n} \\ a {}^{m} \div a {}^{n} = a {}^{m - n} \\ (a {}^{m} ) {}^{n} = a {}^{m \times n} \\ (a \times b) {}^{m} = a {}^{m} \times {}^{m} \\ ( \frac{a}{b} ) {}^{m} = \frac{a {}^{m} }{b {}^{m} } \\ a {}^{0} = 1 \\ a {}^{ - m} = \frac{1}{a {}^{m} } [/tex][tex]1.[/tex][tex]99 {}^{3} \times 99 {}^{3} \div 99 {}^{4} = [/tex][tex] = 99 {}^{3 + 3 - 4} [/tex][tex] = 99 {}^{6 - 4} [/tex][tex] = 99 {}^{2} [/tex][tex] = 99 \times 99[/tex][tex] = 9.801[/tex]==========================[tex]2.[/tex][tex]8 {}^{3} \times 3 {}^{3} = [/tex][tex] = (8 \times 8) \times 8 \times (3 \times 3 ) \times 3[/tex][tex] =( 64 \times 8) \times (9 \times 3)[/tex][tex] = 512 \times 27[/tex][tex] = 13.824[/tex]](https://id-static.z-dn.net/files/de6/05fe21a749c276f27cc96b7b56ede562.jpg)
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Last Update: Sat, 16 Apr 22