Jawaban:

5.

a. V = p × l × t

V = 6cm × 3cm × 4cm

V = 72cm³

b. Lp = 2 × ((p × l) + (p × t) + (l × t))

Lp = 2 × ((6cm × 3cm) + (6cm × 4cm) + (3cm × 4cm))

Lp = 2 × (18cm² + 24cm² + 12cm²)

Lp = 2 × 54cm²

Lp = 108cm²

c. Panjang kawat yang dibutuhkan =

4 × (6cm + 3cm + 4cm)

= 4 × (13cm)

= 52cm

6.

a. V = s³

V = (23cm)³

V = 12.167cm³

b. Lp = 6 × s²

Lp = 6 × (23cm)²

Lp = 6 × 529cm²

c. Panjang kawat yang dibutuhkan =

8 × 23cm

= 184cm

7. 4 × (15cm + 12cm + 13cm)

= 4 × (40cm)

= 160cm

24m = 240cm

240cm : 160cm = 1,5

Kerangka yang dapat dibuat adalah 1

8. Luas jaring-jaring kubus = 6 × s²

150cm² = 6 × s²

150cm² : 6 = s²

25cm² = s²

√25cm² = s²

s = 5cm

9. 180cm : 8

= 22,5cm

10. 92cm = 4 × (p + 5cm + 8cm)

92cm = 4 × (p + 13cm)

92cm : 4 = p + 13cm

23cm = p + 13cm

p = 23cm - 13cm

p = 10cm

Semoga membantu

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