Tolong bantu bsk mau dikumpulkan-!!DICARI:: KELILING DAN LUAS ​

Berikut ini adalah pertanyaan dari feliciaaqilaquuen pada mata pelajaran Matematika untuk jenjang Sekolah Dasar

Tolong bantu bsk mau dikumpulkan-!!
DICARI:: KELILING DAN LUAS ​
Tolong bantu bsk mau dikumpulkan-!!DICARI:: KELILING DAN LUAS ​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawaban :

Jawaban :L = 915 cm²

Jawaban :L = 915 cm²K= 143,7 cm

Penjelasan dengan langkah-langkah:

L¹ = ½ a × t

L¹ = ½ a × t = ½ 15 × 20

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cm

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cm

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cmK⁴ = ½ × π × r

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cmK⁴ = ½ × π × r = ½ × 3,14 × 10

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cmK⁴ = ½ × π × r = ½ × 3,14 × 10 = 15,7 cm

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cmK⁴ = ½ × π × r = ½ × 3,14 × 10 = 15,7 cm total = 40 + 27 + 41 + 15,7

L¹ = ½ a × t = ½ 15 × 20 = 15 × 10 = 150 cm²L² = ½ 9 × 12 = 108 cm²L³ = p × l = 25 × 20 = 500 cm²L⁴ = ½ × 3,14 × 10 × 10 = ½ × 314 = 157 cm²Total = L¹ + L² + L³ + L⁴ = 150 + 108 + 500 + 157 = 915 cm²K¹ = 15 + 25 = 40 cmK² = 12 + 15 = 27 cm K³ = 25 + 16 = 41 cmK⁴ = ½ × π × r = ½ × 3,14 × 10 = 15,7 cm total = 40 + 27 + 41 + 15,7 = 143,7 cm

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Last Update: Sun, 15 Jan 23