Jawaban:

Bangun Ruang Lengkung

Penjelasan dengan langkah-langkah:

Luas permukaan

1/2 bola + Selimut tabung + Selimut kerucut

(1/2.4πr²) +( 2πrt) + (πrs)

1/2(4x3,14x5x5) + (2x3,14x5x12) + (3,14x5x13)

(2x3,14x25) + (3,14x10x12) + (3,14x65)

(3,14x50) + (3,14x120) + (3,14x65)

(157) + (376,8) + (204,1)

737,9 cm²

Volume

1/2 bola + Tabung + Kerucut

1/2(4/3πr³) + (πr²xt) + (1/3xπr²xt)

(4/6x3,14x5³) + (3,14x5x5x12) + (1/3x3,14x5x5x12)

(2/3x3,14x125) + (3,14x25x12) + (1/3x3,14x25x12)

(2/3x392,5) + ( 3,14x300 ) + (4x3,14x25)

(785/3) + (942) + (314)

(785/3) + 1.256

(785/3) + 1.256

(785/3) + (3.768/3)

(4.553/3)

1.517 2/3 cm³

Catatan

tinggi kerucut

t =√(s)²-(r)²

=√(13)²-(5)²

=√(169)-(25)

=√(144)

=12 cm

Detail Jawaban

Mapel: Matematika

Kelas: 9 / IX SMP

Materi: Bangun Ruang Lengkung

Kode Kategorisasi: -

Kata Kunci: Bangun Ruang Lengkung

Demikian

Semoga membantu dan bermanfaat!