Jawaban:

To calculate the resistance and inductance, we first need to find the amplitude of the current:

I = 4 sinq(314t - 45°)

The amplitude of the current is 4 A, so we can write:

I = 4 sin q

where q = 314t - 45°.

Next, we can use Ohm's law to find the impedance of the circuit:

Z = V/I

where V is the voltage and I is the current. The voltage is given as:

V = 566 sin 314t

Substituting for V and I, we get:

Z = (566 sin 314t) / (4 sin q)

= 141.5 / sin q

Since Z = R + jX, where R is the resistance and X is the reactance, we can separate the real and imaginary parts of Z:

R + jX = 141.5 / sin q

R = 141.5 cos q ≈ 100 Ω

X = 141.5 sin q ≈ 100 Ω

So the resistance and inductance of the circuit are approximately equal to 100 Ω.

To find the power factor, we can use the formula:

PF = cos θ

where θ is the phase angle between the voltage and current. In this case, the current leads the voltage by 45°, so:

PF = cos 45° = 0.707

To find the real power, we can use the formula:

P = VI cos θ

where V is the voltage and I is the current. Substituting for V, I, and PF, we get:

P = (566)(4)(0.707) = 1592 W

To find the apparent power, we can use the formula:

S = VI

Substituting for V and I, we get:

S = (566)(4) = 2264 VA

To find the reactive power, we can use the formula:

Q = VSinθ

Substituting for V, I, and PF, we get:

Q = (566)(4)(0.707) = 1270 VAR

So the resistance of the circuit is approximately 100 Ω, the inductance is approximately 100 Ω, the power factor is 0.707, the real power is 1592 W, the apparent power is 2264 VA, and the reactive power is 1270 VAR.