Berikut ini adalah pertanyaan dari jesicanathania22 pada mata pelajaran Matematika untuk jenjang Sekolah Dasar
2. 2x² - 4x-16 = 0
3. -5x² + 40x=0
4. -3x² +8x-1=0
5. 4x² + 11x-7=0
Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
Jawab:
Penjelasan dengan langkah-langkah:
1. x² + x - 3 = 0
x₁,₂ = {-1 ± √(1² - 4 (1) (-3))}/(2(1))
x₁,₂ = {-1 ± √(1 + 12)}/2
x₁,₂ = {-1 ± √13}/2
x₁ = {-1 + √13}/2
x₂ = {-1 - √13}/2
2. 2x² - 4x - 16 = 0
x₁,₂ = {-(-4) ± √((-4)² - 4 (2) (-16))}/(2(2))
x₁,₂ = {4 ± √(16 + 128)}/4
x₁,₂ = {4 ± √144}/4
x₁,₂ = {4 ± 12}/4
x₁ = {4 + 12}/4 = 4
x₂ = {4 - 12}/4 = -2
3. -5x² + 40x = 0
-x (5x - 40) = 0
x₁ = 0
5x - 40 = 0
5x = 40
x₂ = 40/5 = 8
4. -3x² + 8x - 1 = 0
x₁,₂ = {-8 ± √(8² - 4 (-3) (-1))}/(2(-3))
x₁,₂ = {-8 ± √(64 - 12)}/(-6)
x₁,₂ = {-8 ± √52}/(-6)
x₁ = {-8 + √52}/(-6) = {-8 + 2√13}/(-6) = {4 - √13}/3
x₂ = {-8 - √52}/(-6) = {-8 - 2√13}/(-6) = {4 + √13}/3
5. 4x² + 11x - 7 = 0
x₁,₂ = {-11 ± √(11² - 4 (4) (-7))}/(2(4))
x₁,₂ = {-11 ± √(121 + 112)}/(8)
x₁,₂ = {-11 ± √233}/(8)
x₁ = {-11 + √233}/(8)
x₂ = {-11 - √233}/(8)






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Last Update: Wed, 05 Apr 23