Jawab:

{x, y, z} =

{1, 1, 1}

Penjelasan dengan langkah-langkah:

x + 2y + 3z = 6, maka

x = 6 - 2y - 3z (pers i)

2x - y + z = 2 (pers ii)

3x + 2y - z = 4 (pers iii)

Cari y

Substitusi pers ii dan iii dgn pers i

2(6 - 2y - 3z) - y + z = 2

3(6 - 2y - 3z) + 2y - z = 4

↓

12 - 4y - 6z - y + z = 2

18 - 6y - 9z + 2y - z = 4

↓

12 - 2 = 4y + y + 6z - z

18 - 4 = 6y - 2y + 9z + z

↓

10 = 5y + 5z (pers iv)

14 = 4y + 10z (pers v)

Eliminasi

10 = 5y + 5z / × 10 / → 100 = 50y + 50z

14 = 4y + 10z / × 5 / → 70 = 20y + 50 z

____________________________ -

30 = 30y

y = 1

========

Cari z

10 = 5(1) + 5z

10 = 5 + 5z

5z = 10 - 5

5z = 5

z = 1

========

Cari x

x = 6 - 2y - 3z

x = 6 - 2(1) - 3(1)

x = 6 - 2 - 3

x = 1

========

- jiazheng -