Answer:

>>> Chemistry

The reaction between magnesium (Mg) and oxygen (O2) produces magnesium oxide (MgO) with the following reaction formula:

The reaction between magnesium (Mg) and oxygen (O2) produces magnesium oxide (MgO) with the following reaction formula: 2 Mg + O2 → 2 MgO

The reaction between magnesium (Mg) and oxygen (O2) produces magnesium oxide (MgO) with the following reaction formula: 2 Mg + O2 → 2 MgOTo determine the mass of the resulting solid magnesium oxide, we need to use the law of conservation of mass which states that the initial mass of the reactants is equal to the final mass of the products. Therefore, we can calculate the mass of the resulting magnesium oxide in the following way:

Calculate the number of moles of magnesium and oxygen that reacted, The molar mass of Mg is 24.3 g/mol, and the molar mass of O2 is 32 g/mol.

Mol Mg = mass / molar mass = 2g / 24.3 g/mol = 0.082 mol

/ 24.3 g/mol = 0.082 molMoles O2 = mass / molar mass = 10g / 32 g/mol = 0.3125 mol

• Number 2

Determine the balanced reaction between magnesium and oxygen. In this case, the equivalent reaction is 2:1, meaning that two moles of magnesium react with one mole of oxygen.

• Number 3

Calculate the number of moles of magnesium oxide produced. Since the balanced reaction is 2:1, the number of moles of magnesium oxide produced is equal to the number of moles of magnesium reacting.

→ Mol MgO = 0,082 mol

• Number 4

Calculate the mass of the resulting magnesium oxide. The molar mass of MgO is 40.3 g/mol.

→ Mass of MgO = moles x molar mass = 0.082 mol x 40.3 g/mol = 3.29 g

Thus, the equivalent reaction between magnesium and oxygen is 2 Mg + O2 → 2 MgO, and the resulting solid mass of magnesium oxide is 3.29 grams.

sorry if wrong :)

• 2 March 2023