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The volume of 26.4 g carbon dioxide at r. t. p. is 14.6616 dm³.
The massof helium in the flask is0.0196 gram.
Explanation with steps
The problems can be solved with the ideal gas equation because it's low pressure at RTP (room temperature and pressure). This law is related to pressure, volume, temperature, and the molar amount of the gas. The ideal gas equation is given :
Where :
- P = pressure (atm).
- V = volume of the gas (L).
- n = the amount of gas (mole).
- R = the ideal gas constant
R = 0.082 L atm / mole / K - T = the temperature of the gas (K).
Number 24a
Given :
- m CO₂ = 26.4 g
- Ar C = 12 g/mol
Ar O = 16 g/mol - R.T.P or room temperature and pressure means :
R = 0.082 L.atm/mole/K
T = 25°C or 298 K
P = 1 atm
Asked :
- The volume of CO₂ in dm³ = ?
Solution :
Step 1
Calculate Mr CO₂
- Mr CO₂ = Ar C + 2 x Ar O
Mr CO₂ = 12 + 2 x 16
Mr CO₂ = 44 g/mol
Step 2
Calculate mole of CO₂
- n CO₂ = m CO₂ : Mr CO₂
n CO₂ = 26.4 g : 44 g/mol
n CO₂ = 0.6 mole
Step 3
Calculate volume of CO₂
- P x V = n x R x T
1 x V = 0.6 x 0.082 x 298
V = 14.6616 L
V = 14.6616 dm³
Conclusion :
The volume of CO₂ is 14.6616 dm³.
Number 24b
Given :
- V He = 120 cm³
V He = 0.12 dm³
V He = 0.12 L - Ar He = 4.0 g/mol
- R.T.P or room temperature and pressure means :
R = 0.082 L.atm/mole/K
T = 25°C or 298 K
P = 1 atm
Asked :
- The mass of He in the flask = ?
Solution :
Step 1
Calculate mole of Helium gas
- P x V = n x R x T
1 x 0.12 = n x 0.082 x 298
1 x 0.12 = n x 24.436
n = 0.12 : 24.436
n = 0.0049 moles.
Step 2
Calculate mass of Helium gas
Helium gas is He.
- m He = n He x Mr CO₂
m He = 0.0049 moles x 4 g/mole
m He = 0.0196 gram.
Conclusion :
The mass of helium gas is 0.0196 gram.
Learn more
- About other problems and solutions of the ideal gas law :
yomemimo.com/tugas/4622903
yomemimo.com/tugas/51464957
yomemimo.com/tugas/51360973
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Details of solution
Class : X
Subject : Chemistry
Chapter : Fundamental chemistry laws
Code : 10.7.6
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Last Update: Mon, 31 Oct 22