Massa CH₃COONa adalah 164 gram.

Penjelasan dengan langkah-langkah:

Diketahui:

V = 200 mL

pH = 9

Ka = 10⁻⁵

Ar H = 1

Ar C = 12

Ar O = 16

Ar S = 32

Ditanyakan:

massa CH₃COONa

Jawab:

• Menentukan pOH larutan.

pOH = 14 - pH

pOH = 14 - 9

pOH = 5

• Menentukan konsentrasi ion OH⁻.

pOH = - log [OH⁻]

5 = - log [OH⁻]

[OH⁻] = 10⁻⁵ M

• Menentukan konsentrasi CH₃COONa.

[OH⁻] = √(Kw/Ka) [G]

10⁻⁵ = √(10⁻¹⁴/10⁻⁵) [G]

(10⁻⁵)² = 10⁻⁹/[G]

10⁻¹⁰ = 10⁻⁹/[G]

[G] = 10 M

• Menentukan massa CH₃COONa.

M CH₃COONa = (m/Mr) x (1000/mL)

10 = (m/82) x (1000/200)

10 = m/82 x 5

10 x 82 = 5m

5m = 820

m CH₃COONa = 820/5

m CH₃COONa = 164 gram

Pelajari lebih lanjut

• pH hidrolisis asam yomemimo.com/tugas/164924, yomemimo.com/tugas/9654145
• pH hidrolisis basa yomemimo.com/tugas/21760885, yomemimo.com/tugas/22211768

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