Penjelasan:

Jawaban ke 1 :

Rumus : (V1 × M1) + (V2 × M2) / V1 + V2

: -Log (√Ka × Ma )

jawab :

= (V1 × M1) + (V2 × M2) / V1 + V2

= (60 mL × 0,05 M) + (40 mL × 0,05 M) / 100 mL

= (3 mmol) + (2 mmol) / 100 mL

= (5 mmol) / 100 mL

= 0,05 mol

pH = -Log (√ Ka × Ma)

pH = -Log (√ 2 × 10^-5 × [0,05 M] )

pH = -Log (√ 1 × 10^-6 )

pH = -Log ( 1 × 10^-3 )

pH = 3-Log 1

pH = 3

Jawaban ke 2 :

pOH = 14 - (-Log(√Ka × Ma))

pOH = 14 - (-Log(√2 × 10^-5 × [0,05 M]))

pOH = 14 - (-Log(√1 × 10^-6))

pOH = 14 - (-Log(1 × 10^-3))

pOH = 14 - (3-Log 1)

pOH = 14 - 3

pOH = 11