Jawaban:

FeS + O2 → Fe2O3 + SO2

Molar mass (M)

FeS = 119.97 g/mol

O2 = 32.00 g/mol

Fe2O3 = 159.69 g/mol

SO2 = 64.06 g/mol

Reaksi:

FeS + O2 → Fe2O3 + SO2

Moles

FeS = (1 mol/119.97 g) × 1 g = 0.0083 mol

O2 = (1 mol/32.00 g) × 2 g = 0.0625 mol

Fe2O3 = (1 mol/159.69 g) × 3 g = 0.0188 mol

SO2 = (1 mol/64.06 g) × 2 g = 0.0313 mol

Balancing the equation

FeS + O2 → Fe2O3 + SO2

0.0083 mol + 0.0625 mol → 0.0188 mol + 0.0313 mol

0.0083 mol + 0.0625 mol = 0.0908 mol

0.0188 mol + 0.0313 mol = 0.0501 mol

0.0908 mol = 0.0501 mol

Jadi, persamaan reaksi dapat dituliskan sebagai berikut:

FeS + 2O2 → 2Fe2O3 + 2SO2