Since the result is negative, it means that Malik has not yet reached the point where he meets David. In other words, they are still 2 km apart. To solve this problem we use the velocity formula.

Penjelasan dengan langkah-langkah:

Is known:

At 14.30, david left monas and cycled towards istora senayan at speed of 10 km/h.

At the same time , malik left istora senayanv and cyled towards monas at a2 km /h along the same road.

If the distance between monas and istora senayan was 6 km,

Asked:

How far apart were the boys 15 minutes later​

Answer:

We can start by using the formula:

distance = speed x time

Let's begin with David. He cycled for 15 minutes, which is 0.25 hours, at a speed of 10 km/h. So his distance from Monas can be calculated as:

distance_david = speed_david x time_david

distance_david = 10 km/h x 0.25 h

distance_david = 2.5 km

Next, let's calculate Malik's distance from Monas. Since he cycled towards Monas, his initial distance from Monas would be:

distance_malik = distance_between_monas_istora - distance_david

distance_malik = 6 km - 2.5 km

distance_malik = 3.5 km

Now, Malik cycled towards Monas at a speed of 2 km/h for 15 minutes, which is also 0.25 hours. So his distance from Monas can be calculated as:

distance_malik = speed_malik x time_malik

distance_malik = 2 km/h x 0.25 h

distance_malik = 0.5 km

Therefore, after 15 minutes, David is 2.5 km away from Monas and Malik is 0.5 km away from Monas. To find out how far apart they are, we can subtract their distances:

distance_apart = distance_malik - distance_david

distance_apart = 0.5 km - 2.5 km

distance_apart = -2 km

Since the result is negative, it means that Malik has not yet reached the point where he meets David. In other words, they are still 2 km apart.

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