Berikut ini adalah pertanyaan dari masturahnazifa pada mata pelajaran Kimia untuk jenjang Sekolah Menengah Atas
4) Ammonia gas can be prepared through reaction between nitrogen gas andhydrogen gas.
(a) Write the chemical equation for the preparation of ammonia.
(b) 600 cm³ of nitrogen gas is mixed with 600 cm³ of hydrogen gas at room
conditions.
Determine which reactant is used in excess. Calculate the maximum volume of
ammonia produced from the reaction.
[1 mol of ammonia gas accupies 24 dm³ at room conditions]
(a) Write the chemical equation for the preparation of ammonia.
(b) 600 cm³ of nitrogen gas is mixed with 600 cm³ of hydrogen gas at room
conditions.
Determine which reactant is used in excess. Calculate the maximum volume of
ammonia produced from the reaction.
[1 mol of ammonia gas accupies 24 dm³ at room conditions]
Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
Jawaban:
- (a) The chemical equation for the preparation of ammonia gas through the reaction between nitrogen gas and hydrogen gas is:
N2 + 3H2 -> 2NH3
- (b) 600 cm³ of nitrogen gas is equal to 600/24 = 25 dm³. Since the molecular weight of nitrogen is 28 g/mol, the mass of 25 dm³ of nitrogen gas is 25 x 28 = 700 g. Similarly, the mass of 600 cm³ of hydrogen gas is 600/24 x 2 = 100 g.
Since the ratio of nitrogen to hydrogen in the reactants is 1:3, the limiting reactant is the one that is present in the lesser amount. In this case, the limiting reactant is hydrogen gas, as it is present in a lesser amount than nitrogen gas. Therefore, the maximum volume of ammonia that can be produced from this reaction is 100/2 = 50 dm³.
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Last Update: Sat, 25 Mar 23