Jawaban:

2.Ek=Em-Ep=1.520-800=720Joule(energi kinetik)

Ep=M.G.H

800=40.10.H

800=400.H

800/400=H

2Meter=H (Tinggi)

Ek=½Mv²

720=½.40.V²

720=20V²

36=V²

V=6m/s (kecepatan)

3.Ek=½Mv²

Ek=½.500.4²

Ek=250.16

Ek=4000 Joule

Ep=Em-Ek

Ep=4.500-4.000

Ep=500 Joule

Ep=MGH

500=500.10.H

500=5000H

h=1/10 meter

4.Ek=Em-Ep

Ek=7.500-3.500

Ek=4.000 joule

Ep=mgh

Ep=50.10.h

3.500=500h

h=7 meter

Ek=½mv²

Ek=½.50.v²

4.000=25v²

160=V²

V=√160

V=4√10 M/S

5.Ek=½mv²

Ek=½.40.6²

Ek=½×40×36

Ek=20×36

Ek=720 Joule

Ep=12.500-720

Ep=11.780 Joule

11.780=mgh

11.780=40.10.h

11.780=400.h

h=29,45Meter