Jawaban:

since it is given that 50 gms water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.

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final temperature of the mixture =

= [ m1 * T1 + m2 * T2 ] / (m1 + m2)

= [ 50 gms * 20⁰ C + 50 gms * 40⁰C ] / (50+50)

= 3,000 / 100 = 30⁰C

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another way using specific heats :

let the final temperature be = T ⁰C

Amount of heat given out by the hot water = m * s * (40⁰C - T)

= 50 gms * s* (40 -T)

Amount of heat taken in by the cold water = m * s * (T - 20⁰C)

= 50 gms * s * (T - 20 )

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