Penjelasan:

Jawaban:

4,575 cm³

Penjelasan:

diket :

v = 500 cm³

ΔT = (70 - 20)°C = 50°C

\begin{gathered}α \: kaca= 9 \times {10}^{ - 6} /°C \\ γ = 21 \times {10}^{ - 5} \end{gathered}αkaca=9×10−6/°Cγ=21×10−5

ditanya : v yg tumpah = ... ?

penyelesaian :

v akhir kaca

\begin{gathered}vt = vo(1 + 3α \times Δt) \\ = 500 (1 + 3 \times {9.10}^{ - 6} \times 50) \\ = 500 (1 + 135 {.10}^{ - 5} ) \\ = 500 \times 1.00135 \\ = 500.675 \: {cm}^{3} \end{gathered}vt=vo(1+3α×Δt)=500(1+3×9.10−6×50)=500(1+135.10−5)=500×1.00135=500.675cm3

v akhir air

\begin{gathered}vt = vo(1 + γ \times Δt) \\ = 500(1 + {21.10}^{ - 5} \times 50) \\ = 500(1 + {105.10}^{ - 4} ) \\ = 500 \times 1.0105 \\ = 505.25 { \: cm}^{3} \end{gathered}vt=vo(1+γ×Δt)=500(1+21.10−5×50)=500(1+105.10−4)=500×1.0105=505.25cm3

volume yg tumpah

= 505,25 - 500,675

= 4,575 cm³