Penjelasan:

dari gambar dapat dihitung:

a) mencari hambatan pengganti, R

(R1+R2) || R3 || (R4+R5) =

(20+10) || 60 || (40+20) =

30 || 60 || 60 => Rp1

1/Rp1 = 1/30 + 1/60 + 1/60

= (2+1+1)/60 = 4/60

maka Rp1 = 60/4 = 15 ohm

(R6+R7) || R8 || (R9+R10) =

(100+80) || 90 || (40+20) =

180 || 90 || 60 => Rp2

1/Rp2 = 1/180 + 1/90 + 1/60

= (1+2+3)/180 = 6/180

maka Rp1 = 180/6 = 30 ohm

R pengganti = Rp1+Rp2 = 15+30

= 45 ohm

b) mencari i total, i1, i2, i3, i4, i5, i6

i total = V/R = 135/45 = 3 A

i1 = (3×15)/30 = 45/30 = 1,5 A

i2 = (3×15)/60 = 45/60 = 0,75A

i3 = (3×15)/60 = 45/60 = 0,75A

i4 = (3×30)/180 = 90/180 = 0,5A

i5 = (3×30)/90 = 90/90 = 1 A

i6 = (3×30)/60 = 90/60 = 1,5 A

c) mencari tegangan di R4, R8, R10

V R4 = i3×R4 = 0,75×40 = 30 V

V R8 = i5×R8 = 1× 90 = 90 V

V R10 = i6×R10 = 1,5 × 20 = 30 V