Penjelasan:

7.

hambatan no 1

R total = 15 + 30 + 60 = 105 ohm

hambatan no 2

R paralel

1/R = 1/30 + 1/60

1/R = (2+1)/60

1/R = 3/60

R = 20 ohm

R total = 20 + 15 = 35 ohm

hambatan no 3

R paralel

1/R = 1/30 + 1/15

1/R = (1+2)/30

1/R = 3/30

R = 10 ohm

R total = 60 + 10 = 70 ohm

hambatan no 4

R total

1/R = 1/15 + 1/30 + 1/60

1/R = (4+2+1)/60

1/R = 7/60

R = 60/7 ohm

R = 8.57 ohm

besar arus dapat di cari dengan rumus

V = IR

I = V/R

jika di asumsikan bahwa tegangan nya konstan dan hanya variabel hambatan yang di ubah maka besarnya arus berbanding terbalik dengan besar hambatan (makin besar hambatan maka arusnya makin kecil). dapat disimpulkan bahwa urutan besar arus terkecil adalah 1, 2, 3, 4.

8. R paralel

1/R = 1/6 + 1/6

1/R = 2/6

R = 6/2

R = 3 ohm

R total = 2 + 3 + 4

R total = 9 ohm

V = IR

V = 2 x 9

V = 18 Volt

9. hambatan seri pada sirkuit paralel = 3 + 9 = 12 ohm

hambatan paralel

1/R = 1/12 + 1/6

1/R = (1+2)/12

1/R = 3/12

R = 12/3

R = 4 ohm

Hambatan total = 2 + 4 + 0.8 = 6.8 ohm

V = IR

I = V/R

I = 17/6.8

I = 2.5 A