Penjelasan:

1)

diketahui:

L = 200cm = 2m

A = 20mm²= 20×10^-6m²

rho= 2,65×10^-8 ohm. m

ditanya:

R =?

jawab:

R = rho. L/A

= 2,65×10^-8 × 2 / 20×10^-6

= 0,265× 10-²

= 2,65×10-³ ohm

2)

diketahui:

L1 = 1,25m

A1 = 25mm²

R1 = 5 ohm

L2 = 5m

A2 = 5mm²

rho 1 = rho 2 = rho (jenis kawat sama)

ditanya:

R2=?

jawab:

R1 = rho. L1/A1

5 = rho. 1,25/25

rho = 25×5/1,25

= 125/1,25

= 100

maka:

R2 = 100.(5)/(5)

= 500/5

= 100 ohm

3)

diketahui:

L = 5 m

A = 10 mm² = 10×10^-6m²

R = 0,5 ohm

ditanya:

rho =?

jawab:

R = rho. L/A

rho = R. A/L

= 0,5×10×10^-6 /5

= 10^-6 ohm. m

4)

diketahui:

La =Lb = L

Aa = 36mm²

Ra = 9 ohm

Rb = 3 ohm

ditanya:

Ab = ?

jawab:

rho = Ra. Aa/ L

= 9×36/L

= (324/L)

maka:

Ab = rho. L/ Rb

= (324/L) × L /3

= 324/3

= 108 mm²