Jawaban:

Diketahui:

table attributes columnalign right center left columnspacing 0px end attributes row cell rho subscript 1 end cell equals cell rho subscript 2 end cell row cell l subscript 1 end cell equals cell 2 l subscript 2 end cell row cell r subscript 2 end cell equals cell 2 r subscript 1 end cell row cell R subscript 1 end cell equals cell 10 space straight capital omega end cell end table

Ditanyakan:

R2?

Jawab:

Persamaan untuk menentukan hambatan kawat:

R equals fraction numerator rho l over denominator A end fraction

dengan demikian, karena nilai hambatan jenis kawat sama, maka perbandingan nilai hambatannya adalah:

R subscript 1 over R subscript 2 equals fraction numerator begin display style bevelled l subscript 1 over A subscript 1 end style over denominator begin display style bevelled l subscript 2 over A subscript 2 end style end fraction R subscript 1 over R subscript 2 equals l subscript 1 over A subscript 1 times A subscript 2 over l subscript 2 R subscript 1 over R subscript 2 equals l subscript 1 over πr subscript 1 squared times πr subscript 2 squared over l subscript 2 R subscript 1 over R subscript 2 equals l subscript 1 over l subscript 2 times r subscript 2 squared over r subscript 1 squared 10 over R subscript 2 equals fraction numerator 2 l subscript 2 over denominator l subscript 2 end fraction times open parentheses 2 r subscript 1 close parentheses squared over r subscript 1 squared 10 over R subscript 2 equals 2 times 4 R subscript 2 equals 10 over 8 R subscript 2 equals 1 comma 25 space straight capital omega

dengan demikian hambatan kawat kedua adalah 1,25 Ω.

Jadi, jawaban yang tepat adalah B.

maaf kalou salah