Penjelasan:

diketahui :

qA = -5 μC = -5 × 10-⁶ C

qB = 10 μC = 10 × 10-⁶ C

qC = -12 μC = -12 × 10-⁶ C

rAB = 6 cm = 6 × 10-² m

rBC = 4 cm = 4 × 10-² m

k = 9 × 10⁹ Nm²/C²

ditanya :

besar dan arah gaya pada muatan B?

Jawab :

FAC = k. qA.qB/r²

FAC = 9.10⁹. (5 × 10-⁶)(10 × 10-⁶)/36 × 10-⁴

FAC = 9.5.10/36 × 10¹ N

FAC = 450/36 × 10 N

FAC = 125 N

FCB = k. qC.qB/r²

FCB = 9.10⁹. (12 × 10-⁶)(10 × 10-⁶)/16 × 10-⁴

FCB = 9.12.10/16 × 10¹ N

FCB = 675 N

besar dan arah gaya pada muatan B :

ΣFB = -125 + 675

ΣFB = 550 N arah ke kanan/muatan C.