a. Hambatan total rangkaian

b. Besar tegangan pada masing-masing lampu

c. Kuat arus yang melalui masing-masing lampu

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a. Hambatan total rangkaian

1/Rp = ⅓ + ⅙ + 1/9 + 1/12

1/Rp = 12/36 + 6/36 + 4/36 + 3/36

1/Rp = 25/36

Rp = 36/25 Ω atau 1,44 Ω

b. Besar tegangan masing masing lampu

Tegangan masing masing lampu sama dengan tegangan rangkaian yaitu 12 V

c. Kuat arus masing masing lampu :

Kuat arus rangkaian :

I = V/R

I = 12/1,44

I = 1200/144

I = 25/3 A

perbandingan arus :

i₁ : i₂ : i₃ : i4 = 12 : 6 : 4 : 3

arus i₁ :

= 12/36 × 25/3

= 2,78 A ✔

arus i₂ :

= 6/36 × 25/3

= ⅙ × 25/3

= 1,389 A ✔

arus i₃ :

= 4/36 × 25/3

= 1/9 × 25/3

= 0,9 A ✔

arus i4 :

= 3/36 × 25/3

= 0,7 A ✔

Kelas : 12

Mapel : Fisika

Materi : Listrik Dinamis

Kata kunci : Arus masing masing, tegangan masing masing