Jawaban:

If a gas at 250 K has a pressure of 0.00008 Pa and the pressure drops to 0.00002 Pa, 62.5 K is the new temperature

Explanation: -

Initial Pressure P₁ = 0.00008 Pa

Final Pressure P₂ = 0.00002 Pa

Initial Temperature T₁ = 250 K

Since the volume is not mentioned, it remains constant.

So initial Volume V₁ = Final volume V₂

Now using the combined gas equation

\frac{P1 V1}{T1}T1P1V1 = \frac{P2 V2}{T2}T2P2V2

Final Temperature T₂ = \frac{P 2 V2 T1}{P1 V1}P1V1P2V2T1

Plugging in the values,

T₂ = \frac{0.00002 Pa x V2 x 250 K}{0.00008 Pa x V1}0.00008PaxV10.00002PaxV2x250K

As V₂ = V₁, they cancel each other.

T₂ = 62.5 K