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Young’s experiment is performed with sodium light (λ = 589

Berikut ini adalah pertanyaan dari jjymii pada mata pelajaran Fisika untuk jenjang Sekolah Menengah Atas

Young’s experiment is performed with sodium light (λ = 589 nm). Fringes are measured carefully on a screen 100 cm away from the double slits, and the center of the twentieth fringe is found to be 11.78 mm from the center of the zeroth fringe. What is the separation of the two slits?​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

In Young's double-slit experiment, the separation between the two slits (d) can be determined from the fringe spacing (s) on the screen using the following formula:

s = λL / d

where λ is the wavelength of light, L is the distance between the double slits and the screen, and s is the distance between adjacent bright fringes (also known as the fringe spacing).

In this problem, we are given λ = 589 nm, L = 100 cm, and the distance between the 0th and 20th fringes (s) as 11.78 mm = 0.01178 m.

Using the formula above, we can solve for d:

d = λL / s = (589 nm) x (100 cm) / 0.01178 m = 4.99 x 10^-4 m

Therefore, the separation between the two slits is approximately 4.99 x 10^-4 m, or about 0.499 mm.

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Last Update: Sun, 16 Jul 23
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