Jawaban:

Diketahui :

V0g = V0a = 500 cm^3

T1 = 0° C

T2 = 22° C

αg = 9 x 10^(-6) /°C

γ a = 1,2 x 10^(-3) /°C

Ditanya :

V = ?

γ g =3×a g

γ g= 3×(9 x 10^(-6))

γ g = 27 x (10^(-6) /°C)

@Ara 1412

Volume alkohol yang tumpah:

V = ΔVa - Δ Vg

V = V0a×γa× (T2 - T1) - V0g×γg× (T2 - T1)

V = 500 ×1,2 x 10^(-3) × (22 -0) - 500 × 27 x 10^(-6) × (22- 0)

V = 500 ×22× (1,2 x 10^(-3) - 27 x 10^(-6))

V = 11000 × (1200 x 0^(-6) - 27 x 10^(-6))

V = 11000 × (1173 x 10^(-6))

V = 12,903 cm^3

@Ara 1412

#Semoga membantu :)