Jawaban:

w = 4.615 litersatm

AE = 0

AH = 4.615 litersatm

q = 9.230 liters*atm

Penjelasan:

The expansion of the gas is isothermal, meaning that the temperature of the gas remains constant during the expansion. This means that the change in internal energy, AE, of the gas is zero.

The work done by the gas, w, is the product of the pressure of the gas and the change in volume of the gas. The initial volume of the gas can be calculated from the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas.

Substituting the known values, we get:

(10 atm)(V) = (3 liters)(0.08206 Latm/molK)(273.15 K)

Solving for V, we find that the initial volume of the gas is 0.923 liters.

The final volume of the gas can be calculated in the same way, using the final pressure of 5 atm:

(5 atm)(V) = (3 liters)(0.08206 Latm/molK)(273.15 K)

Solving for V, we find that the final volume of the gas is 1.846 liters.

The work done by the gas is then:

w = (5 atm)(1.846 liters - 0.923 liters) = 4.615 liters*atm

The change in enthalpy, AH, of the gas is equal to the change in internal energy plus the work done by the gas. Since the change in internal energy is zero, the change in enthalpy is also equal to the work done by the gas:

AH = w = 4.615 liters*atm

The heat transfer, q, for the system is the change in enthalpy of the gas plus the work done by the gas:

q = AH + w = 4.615 litersatm + 4.615 litersatm = 9.230 liters*atm

Thus, the values of w, AE, AH, and q for the system are:

w = 4.615 litersatm

AE = 0

AH = 4.615 litersatm

q = 9.230 liters*atm