a) The type of lens in this scenario is a converging lens, specifically a convex lens.

+ A converging lens, or convex lens, is a lens that is thicker at the center and thinner at the edges. It possesses a positive focal length, causing incident parallel rays of light to converge to a point after passing through the lens.

b) The object should be positioned at a distance equal to four times the focal length of the lens.

+ To achieve the desired upright and virtual image formation, the object needs to be situated at a distance of four times the focal length (4f) from the lens. This placement ensures the necessary ray bending and magnification properties for the image formation.

c) The image will materialize on the same side as the object, situated at a distance equal to one-third of the focal length from the lens.

+ The refracted rays create a virtual image that appears on the same side as the object. This virtual image will be positioned at a distance of one-third of the focal length (f/3) from the lens. The negative sign associated with the image distance indicates its virtual nature and the upright orientation.

Note: For precise determination of the focal length, object placement, and image location, additional numerical values are required.