Answer:

>>> Physics

> 1,91 x 10^-5 tesla

Explain:

→ B is the resulting magnetic field (in tesla)

→ μ0 is the permeability of a vacuum (in henry per meter)

→ I is the current flowing through the wire (in amperes)

→ r is the distance between point P1 and the wire (in meters)

→ π is the constant of pi (about 3.14)

••••••••••••

→ r = 0.131 m (since the distance is given in centimeters, we need to convert it to meters)

→ I = 0.0582 A

→ μ0 = 4π x 10^-7 henry per meter (magnetic constant)

Count it:

→ B = (4π x 10^-7) * (0.0582) / (2 * π * 0.131)

→ B = 1.91 x 10^-5 tesla

B = 1.91 x 10^-5 teslaSo, the magnitude of the magnetic field at P1 is about 1.91 x 10^-5 tesla ✓

• 12 March 2023