LISTRIK STATIS

▶ Rangkaian Kapasitor

C₁ = 6 μF

C₂ = 3 μF

Cp₁ = C₁ + C₂

Cp₁ = 6 + 3  

Cp₁ = 9 μF

C₃ = 6 μF

C₄ = 3 μF

Cs₁ = (C₃ × C₄) / (C₃ + C₄)

Cs₁ = (6 × 3) / (6 + 3)

Cs₁ = 2 μF

C₅ = 6 μF

Cp₂ = Cs₁ + C₅

Cp₂ = 2 + 6

Cp₂ = 8 μF

C₆ = 3 μF

C₇ = 6 μF

Cp₃ = C₆ + C₇

Cp₃ = 3 + 6

Cp₃ = 9 μF

a]

C.total = __ ?

1/C.total = 1/Cp₁ + 1/Cp₂ + 1/C₃

1/C.total = 1/9 + 1/8 + 1/9

C.total = 2,88 μF ✔

b]

muatan tiap kapasitor

V.AB : V.CD : V.EF = 1/Cp₁ : 1/Cp₂ : 1/C₃

V.AB : V.CD : V.EF = 1/9 : 1/8 : 1/9

V.AB = V.EF

V.AB : V.CD = 8 : 9

V.CD = ⁹/₈ V.AB

V.AB + V.CD + V.EF = 18 V

V.AB + ⁹/₈ V.AB + V.AB = 18 V

V.AB = 5,76 V

V.CD = ⁹/₈ × 5,76

V.CD = 6,48 V

V.EF = 5,76 V

V₁ = V₂ = V.AB

Q₁ = C₁ V₁

Q₁ = 6 × 5,76

Q₁ = 34,56 μC ✔

Q₂ = C₂ V₂

Q₂ = 3 × 5,76

Q₂ = 17,28 μC ✔

V₃₄ = V₅ = V.CD = 6,48 V

Q₃ = Q₄ = Cs₁ × V₃₄

= 2 × 6,48

= 12,96 μC ✔

Q₅ = C₅ V₅

Q₅ = 6 × 6,48

Q₅ = 38,88 μC ✔

Q₆ = Q₂ = 17,28 μC ✔

Q₇ = Q₁ = 34,56 μC ✔

c]

beda potensial tiap kapasitor

V₁ = V₂ = V.AB = 5,76 V ✔

V₅ = V.CD = 6,48 V ✔

V₃ = Q₃ / C₃

V₃ = 12,96 / 6

V₃ = 2,16 V ✔

V₄ = V₃₄ - V₃

V₄ = 6,48 - 2,15

V₄ = 4,33 V ✔

V₆ = V₇ = V.EF = 5,76 V ✔

d]

W = __ ?

W = ½ × C.total × V²

W = ½ × 2,88 × 10⁻⁶ × 18²

W ≈ 4,67 × 10⁻⁴ J ✔