2. The distance between the satellite from the surface of

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2. The distance between the satellite from the surface of the Earth is 35000 km. If theradius of the Earth is 6.38 x 106 m, what is the gravitational field of the satellite?​

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Class 11

>>Physics

>>Gravitation

>>Gravitational Potential Energy

>>As you have learnt in the text, a geosta

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As you have learnt in the text, a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth = 6.0×10

24

kg, radius = 6400 km.

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Mass of the Earth,M=6.0×10

24

kg

Radius of the Earth, R=6400 km=6.4×10

6

m

Height of a geostationary satellite from the surface of the Earth, h=36000 km=3.6×10

7

m

Gravitational potential due to Earth's gravity at height h

V=−

R+h

GM

=−

3.6×10

7

+0.64×10

7

6.67×10

−11

×6×10

24

=−9.4×10

6

J/kg

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Last Update: Mon, 16 May 22