Jawaban:

Berikut proses mencari hambatan pengganti

Hambatan bc paralel

1/Rbc = 1/4 + 1/4 = 2/4

Rbc = 4/2 = 2

Hambatan seri a-bc-d

Rabcd = 2 + Rbc + 2 = 2 + 2 + 2 = 6

Hambatan af paralel

1/Raf = 1/2 + 1/2

1/Raf = 2/2

Raf = 1

Hambatan Raf dan 2 ohm diseri

Rafd = Raf + 2

Rafd = 1 + 2 = 3

Hambatan Rafd dan Rabcd diparalel

1/Rad = 1/Rabcd + 1/Rafd

1/Rad = 1/6 + 1/3

1/Rad = 1/6 + 2/6

1/Rad = 3/6

Rad = 6/3 = 2

Hambatan total 2 dan Rad dan 2 diseri

Rt = 2 + Rad + 2

Rt = 2 + 2 + 2

Rt = 6 ohm

V = 12 volt

I = ?

V = IR

I = V/R

I = 12/6 = 2 Ampere

Penjelasan: