Jawaban:

Kuat Medan Gravitasi

Penjelasan:

Diketahui:

M₁=40 kg

r₁ = 8 m

M₂= 30 kg

r₂ = 4 m

Asumsi θ= 60⁰

Ditanya

Fr = ...

Jawaban

Benda 1

g₁ = GM₁

r₁²

= G(40)

8²

= 40G

64

= 0,625G

Benda 2

g₂ = GM₂

r₂²

= G(30)

4²

= 30G

16

= 1,875 G

Fr = √(g₁)²+(g₂)²+2g₁g₂cosθ

= √(0,625)²+(1,875)²+2(0,625)(1,875)cos60⁰

= √(5/8)²+(15/8)²+2(5/8)(15/8)1/2)

= √(5/8)²+(15/8)²+(5/8)(15/8)

= √(25/64)+(225/64)+(75/64)

= √(250/64)+(75/64)

= √(325/64)

= √(25x13)/(64)

= 5√(13)G{✓}

8

= 5√(13) x (6,67 x 10⁻¹¹)

8

= 2,25 x (6,67 x 10⁻¹¹)

= 15,0306 x 10⁻¹¹ N

= 1,50306 x 10⁻¹⁰ N {✓}

Ketetapan

Konstanta gravitasi

G = 6,67 x 10⁻¹¹ Nm²/kg²

Detail Jawaban:

Mapel : Fisika

Kelas : 10 / X SMA

Materi : Kuat Medan Gravitasi

Kode Kategorisasi : -

Kata Kunci : Kuat Medan Gravitasi

Demikian

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