ppp23 + 52.331 =f(x) = x! - 1² + x²

Berikut ini adalah pertanyaan dari VioCanszZ pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Ppp23 + 52.331 =

f(x) = x! - 1² + x² × x⁵
f(2) = ??

Lim (12x + 13x ÷ 6)
x → 3

5 poin ​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawaban:

23 + 52.331 =

→ 23 + 52.331 =

52.354

f(x) = x! - 1² + x² × x⁵

f(2) = ??

f(x) = x! - 1² + x² × x⁵

f(2) = 2! - 1² + 2² × 2⁵

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) )

f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 )

f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )

f(2) = 2 - 1 + ( 4 × 64 )

f(2) = 2 - 1 + 256

f(2) = 1 + 256

f(2) = 257

Lim (12x + 13x ÷ 6)

x → 3

→ 12(3) + 13(3) ÷ 6 =

→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =

→ 36 + ( 39 ÷ 6 ) =

→ 36 + 6,5 =

42,5

Penjelasan dengan langkah-langkah:

I Hope This Help

Jawaban:23 + 52.331 = → 23 + 52.331 =→ 52.354f(x) = x! - 1² + x² × x⁵f(2) = ??f(x) = x! - 1² + x² × x⁵ f(2) = 2! - 1² + 2² × 2⁵ f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 ) f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )f(2) = 2 - 1 + ( 4 × 64 ) f(2) = 2 - 1 + 256f(2) = 1 + 256f(2) = 257Lim (12x + 13x ÷ 6)x → 3→ 12(3) + 13(3) ÷ 6 =→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =→ 36 + ( 39 ÷ 6 ) =→ 36 + 6,5 =→ 42,5Penjelasan dengan langkah-langkah:I Hope This HelpJawaban:23 + 52.331 = → 23 + 52.331 =→ 52.354f(x) = x! - 1² + x² × x⁵f(2) = ??f(x) = x! - 1² + x² × x⁵ f(2) = 2! - 1² + 2² × 2⁵ f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 ) f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )f(2) = 2 - 1 + ( 4 × 64 ) f(2) = 2 - 1 + 256f(2) = 1 + 256f(2) = 257Lim (12x + 13x ÷ 6)x → 3→ 12(3) + 13(3) ÷ 6 =→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =→ 36 + ( 39 ÷ 6 ) =→ 36 + 6,5 =→ 42,5Penjelasan dengan langkah-langkah:I Hope This HelpJawaban:23 + 52.331 = → 23 + 52.331 =→ 52.354f(x) = x! - 1² + x² × x⁵f(2) = ??f(x) = x! - 1² + x² × x⁵ f(2) = 2! - 1² + 2² × 2⁵ f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 ) f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )f(2) = 2 - 1 + ( 4 × 64 ) f(2) = 2 - 1 + 256f(2) = 1 + 256f(2) = 257Lim (12x + 13x ÷ 6)x → 3→ 12(3) + 13(3) ÷ 6 =→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =→ 36 + ( 39 ÷ 6 ) =→ 36 + 6,5 =→ 42,5Penjelasan dengan langkah-langkah:I Hope This HelpJawaban:23 + 52.331 = → 23 + 52.331 =→ 52.354f(x) = x! - 1² + x² × x⁵f(2) = ??f(x) = x! - 1² + x² × x⁵ f(2) = 2! - 1² + 2² × 2⁵ f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 ) f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )f(2) = 2 - 1 + ( 4 × 64 ) f(2) = 2 - 1 + 256f(2) = 1 + 256f(2) = 257Lim (12x + 13x ÷ 6)x → 3→ 12(3) + 13(3) ÷ 6 =→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =→ 36 + ( 39 ÷ 6 ) =→ 36 + 6,5 =→ 42,5Penjelasan dengan langkah-langkah:I Hope This HelpJawaban:23 + 52.331 = → 23 + 52.331 =→ 52.354f(x) = x! - 1² + x² × x⁵f(2) = ??f(x) = x! - 1² + x² × x⁵ f(2) = 2! - 1² + 2² × 2⁵ f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( ( 2 × 2 ) × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 2 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 4 × 2 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 8 × 2 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 16 × 2 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × ( 32 × 2 ) ) f(2) = ( 2 × 1 ) - ( 1 × 1 ) + ( 4 × 64 ) f(2) = 2 - ( 1 × 1 ) + ( 4 × 64 )f(2) = 2 - 1 + ( 4 × 64 ) f(2) = 2 - 1 + 256f(2) = 1 + 256f(2) = 257Lim (12x + 13x ÷ 6)x → 3→ 12(3) + 13(3) ÷ 6 =→ ( 12 × 3 ) + ( ( 13 × 3 ) ÷ 6 ) =→ 36 + ( 39 ÷ 6 ) =→ 36 + 6,5 =→ 42,5Penjelasan dengan langkah-langkah:I Hope This Help

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Last Update: Tue, 21 Jun 22