Jawaban :

1. Langkah 1 : Menghitung mol gas argon

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P V end cell equals nRT row cell 10 to the power of 5 space Pa cross times 3 cross times 10 to the power of negative sign 3 end exponent space mL end cell equals cell n cross times 8 comma 314 space J forward slash mol space K cross times 300 space K end cell row cell 3 cross times 10 squared end cell equals cell n cross times 2494 comma 2 space J forward slash mol end cell row n equals cell fraction numerator 3 cross times 10 squared over denominator 2494 comma 2 space J forward slash mol end fraction end cell row n equals cell 0 comma 120 space mol end cell end table end style

Langkah 2 : Menghitung jumlah partikel gas argon

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell jumlah space partikel end cell equals cell n cross times L end cell row blank equals cell 0 comma 120 space mol cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 72 cross times 10 to the power of 23 space partikel end cell end table end style

Sehingga, banyak partikel gas argon dalam tabung tersebut adalah begin mathsize 14px style 0 comma 72 cross times 10 to the power of 23 space partikel end style.

2. Jawab :

Diketahui :

w = 240 rpm

= 240 x 2\pi rad

_____________

60 sekon

= 8\pi rad/sekon

Ditanya :

V = ....?

Jawab :

Kita gunakan rumus hubungan kecepatan linear dengan kecepatan sudut :

V = wr

V = (8\pi)(2)

V = 16\pi m/s

Semoga Membantu :>

Kalau jawaban saya disukai oleh kakak/abang tolong jadikan jawaban saya yang terbaik ya ^^