Jawab:

D.   {y|-3 ≤ y ≤ 1, yER}

Penjelasan dengan langkah-langkah:

Diketahui
f(x) = 2x-2   g(x) = x²-2
Domain (f-g)(x) {0≤x≤3}
Ditanya Range (f-g)(x)

Cari (f-g)(x) dulu
f dikurang g
(2x-2)-(x²-2) =
2x-2-x²+2 =
2x-x² =
-x(x-2)
(f-g)(x) = -x(x-2)

Jika Domain (f-g)(x) {0≤x≤3}
x-nya pake 0 dan 3
Maks. -0(0-2) = 0 belum tentu sampai ada titik balik
y Min. -3(3-2) = -3(1) = -3

Cari titik balik
2x-x²
a = -1, b = 2
x = -b/2a = -2/(2(-1) = -2/-2 = 1
y = 2(1)-1² = 2-1 = 1
y Maks. = 1

Maka range = {y|-3 ≤ y ≤ 1, yER}

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