Jawaban:

Diketahui:

h equals 6 space cm r equals plus 30 space cm s equals 20 space cm

Ditanya: s', M, h', sifat bayangan

Rumus dalam cermin cekung

s apostrophe equals fraction numerator s cross times f over denominator s minus f end fraction M equals open vertical bar fraction numerator s apostrophe over denominator s end fraction close vertical bar space atau space M equals open vertical bar fraction numerator h apostrophe over denominator h end fraction close vertical bar

1) Mencari jarak fokus

f equals r over 2 f equals 30 over 2 f equals plus 15 space cm

2) Mencari jarak bayangan

s apostrophe equals fraction numerator s cross times f over denominator s minus f end fraction s apostrophe equals fraction numerator 20 cross times 15 over denominator 20 minus 15 end fraction s apostrophe equals 300 over 5 bold italic s bold apostrophe bold equals bold 60 bold space bold cm

3) Mencari perbesaran bayangan

M equals open vertical bar fraction numerator s apostrophe over denominator s end fraction close vertical bar M equals open vertical bar 60 over 20 close vertical bar bold italic M bold equals bold 3 bold space bold kali

4) Mencari tinggi bayangan

M equals open vertical bar fraction numerator h apostrophe over denominator h end fraction close vertical bar h apostrophe equals M cross times h h apostrophe equals 3 cross times 6 bold italic h bold apostrophe bold equals bold 18 bold space bold cm

5) Sifat bayangan

Bayangan berada pada ruang III dan bersifat nyata, terbalik, diperbesar

Jadi, jarak bayangan = 60 cm, perbesaran bayangan = 3 kali, tinggi bayangan = 18 cm dan sifat bayangan (pada ruang III) nyata, terbalik, serta diperbesarspace

Penjelasan:

semoga bermanfaat