1. Dua suku berikutnya dari barisan 243, 81, 27, 9,

Berikut ini adalah pertanyaan dari hafizahnoviyanti44 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

1. Dua suku berikutnya dari barisan 243, 81, 27, 9, 3, ... adalah ....2. Rumus suku ke-n pada barisan 56, 49, 42, 35, ... adalah .....
3. Suku ke-10 dari barisan 2, 5, 8, 11, 14, ... adalah ....
tolong bantu jawab ya bsk pagi mau dikumpulin​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

 \mathbb{ \color{aqua}{ \underbrace{JAWABAN}}}

  1. 1 dan
  2. 63 - 7n
  3. 29

------------------

 \mathbb{ \color{orange}{ \underbrace{PENYELESAIAN}}}

SOAL 1 :

 \boxed{ \begin{array}{c|c} \color{violet} \bf Rumus& \color{violet} \bf Keterangan \\ \hline & \tt{\color{magenta} U} \blue{_n} = suku \: ke - n ~~~~~\\ \boxed{ \: \tt {\color{magenta} U} \color{aqua} \blue{_n} = \purple {a} \cdot \green{r}^{ \blue{n} - 1} \: } & \tt \purple{a} = suku \: pertama \\ & \tt \green{r} = rasio \: \left( \frac{U_{2}}{U_{1}} \right) ~~~\end{array} } \\ \\

 \boxed{ \: \begin{aligned} &\tt{a = \purple{243}} \\ &\tt{r = \frac{81}{243} = \green{ \frac{1}{3} }} \end{aligned} \: } \\ \\

  • rumus suku ke-n

 \boxed{ \: \begin{aligned} \tt{U_n} &= \tt{ \purple{a} \cdot { \green{r}}^{n - 1} } \\ \tt{U_n} &= \tt{ \purple{243} \cdot {\left( \green{ \frac{1}{3}} \right)}}^{n - 1} \\ \tt{U_n} &= \tt{ {3}^{5} \cdot {\left( \frac{1}{ {3}^{1} } \right)}^{n - 1} } \\ \tt{U_n} &= \tt{ {3}^{5} \cdot {\left( {3}^{ - 1} \right)} }^{n - 1} \\ \tt{U_n} &= \tt{ {3}^{5} \cdot {3}^{ - n + 1} } \\ \tt{U_n} &= \tt{ {3}^{5 + ( - n) + 1} } \\ \tt{U_n} &= \pink{\tt{ {3}^{6 - n} }} \end{aligned} \:}&\begin{aligned}&\begin{aligned} \red{ \bf{ingat : }}\end{aligned} \\ &\boxed{ \: \begin{aligned} \tt{{a}^{ - n}} &= \tt{ \frac{1}{ {a}^{n} } } \\ \tt{ {( {a}^{m} )}^{n} } &= \tt{ {a}^{m \times n} } \\ \tt{ {a}^{m} \times {a}^{n} } &= \tt{ {a}^{m + n} } \end{aligned} \: }\end{aligned} \\ \\

  • dua suku berikutnya (U6 dan U7)

 \boxed{ \: \begin{array}{c|c} \begin{aligned} \tt{U_{n}} &= \tt{ {3}^{6 - n} } \\ \tt{U_{6}} &= \tt{ {3}^{6 - 6} } \\ \tt{U_{6}} &= \tt{ {3}^{0} } \\ \tt{U_{6}} &= \red{ \boxed{ \pink{ \bf{{1}}}}} \\ \\ \\ \end{aligned}& \begin{aligned} \tt{U_{n}} &= \tt{ {3}^{6 - n} } \\ \tt{U_{7}} &= \tt{ {3}^{6 - 7} } \\ \tt{U_{7}} &= \tt{ {3}^{ - 1} }\\ \tt{U_{7}} &= \small{ \tt{ \frac{1}{ {3}^{1} }}}\\ \tt{U_{7}} &= \small{ \red{ \boxed{ \bf{ \pink{ \frac{1}{3} }}}}} \end{aligned} \end{array} \: }& \begin{aligned} &\begin{aligned} \red{ \bf{ingat : }} \end{aligned} \\ &\boxed{ \: \begin{aligned} \tt{ {a}^{0} } &= \tt{1} \\ \tt{ {a}^{ - n} } &= \tt{ \frac{1}{ {a}^{n} } } \end{aligned} \: } \end{aligned}\\ \\

SOAL 2 :

 \boxed{ \begin{array}{c|c} \color{violet} \bf Rumus& \color{violet} \bf Keterangan \\ \hline & \tt{\color{magenta} U} \blue{_n} = suku \: ke - n ~~~~~~\\ \boxed{ \: \tt {\color{magenta} U} \color{aqua} \blue{_n} = \purple{a} + ( \blue{n} - 1) \orange{b} \: } & \tt \purple{a} = suku \: pertama~ \\ & \tt \orange{b} = beda \: (U_{2} - U_{1}) \end{array} } \\ \\

 \boxed{ \: \begin{aligned} &\tt{a = \purple{56}} \\ &\tt{b = 49 - 56 = \orange{ ( - 7)}} \end{aligned} \: } \\ \\

  • rumus suku ke-n

 \boxed{ \: \begin{aligned}\tt{U_{n}} &= \tt{ \purple{a} + (n - 1) \orange{b}} \\ \tt{U_{n}} &= \tt{ \purple{56} + (n - 1) \orange{( - 7)}} \\ \tt{U_{n}} &= \tt{ \purple{56} - 7n + 7} \\ \tt{U_{n}} &= \red{ \boxed{ \pink{ \tt{63 - 7n}}}} \end{aligned} \: } \\ \\

SOAL 3 :

 \boxed{ \begin{array}{c|c} \color{violet} \bf Rumus& \color{violet} \bf Keterangan \\ \hline & \tt{\color{magenta} U} \blue{_n} = suku \: ke - n ~~~~~~\\ \boxed{ \: \tt {\color{magenta} U} \color{aqua} \blue{_n} = \purple{a} + ( \blue{n} - 1) \orange{b} \: } & \tt \purple{a} = suku \: pertama~ \\ & \tt \orange{b} = beda \: (U_{2} - U_{1}) \end{array} } \\ \\

 \boxed{ \: \begin{aligned} &\tt{a = \purple{2}} \\ &\tt{b = 5 - 2 = \orange{3}} \\ &\tt{n = \blue{10}} \end{aligned} \: } \\ \\

  • suku ke-10

 \boxed{ \: \begin{aligned}\tt{U_{n}} &= \tt{ \purple{a} + ( \blue{n} - 1) \orange{b}} \\ \tt{U_{10}} &= \tt{ \purple{2} + ( \blue{10} - 1) \orange{3}} \\ \tt{U_{10}} &= \tt{ \purple{2} + (9) \orange{3}} \\ \tt{U_{10}} &= \tt{ \purple{2} + 27} \\ \tt{U_{10}}&= \red{ \boxed{ \bf{ \pink{29}}}} \end{aligned} \: }

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Last Update: Sun, 20 Nov 22