Jawaban:

jika

²log 3 = a

³log 5 = b

nyatakan bentuk berikut dalam a dan b!

a.2log 15 = ²log(3x5) = ²log3 + ²log5 = ²log3 + ²log3 x ³log5 = a + ab = a(1 + b)

b.4 log 75 = ³log75/³log4 = ³log(3x5²)/³log2²

= (³log3 + 2³log5)/2³log2

= ( 1 + 2b)/(2/a)

= a( 1 + 2b)/2

c. 25 log 36 = ³log36/³log25

= ³log(2²x3²)/³log5²

= (2³log2 + 2³log3)/2³log5

= (2/a + 2)/2b

= (2 + 2a)/2ab

= (1 + a)/ab

d. ²log 5 = ²log3 x ³log5 = ab

e. 30 log 150

= ³log(2x3x5²)/³log(2x3x5)

= (³log2 + ³log3 + 2³log5)/(³log2 + ³log3 + ³log5)

= (1/a + 1 + 2b)/(1/a + 1 + b)

= (1+a+2ab)/(1 +a+ab)

f. 100 log 50 = ³log(2 x 5²)/³log(2² x 5²)

= (³log2 + 2³log5)/(2³log2 + 2³log5)

= (1/a + 2b) /(2/a + 2b)

= ( 1 + 2ab )/(2 + 2ab)

Penjelasan dengan langkah-langkah:

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