Quis / Quiz kumat ( kuis matematika ) by @Reza01Gaming f(x) =

Berikut ini adalah pertanyaan dari Reza01Gaming pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Quis / Quizkumat ( kuis matematika )
by @Reza01Gaming

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²
f(1) = ...
f(2) = ...
f(3) = ...
f(4) = ...
f(5) = ...
f(6) = ...
f(7) = ...
f(8) = ...
f(9) = ...

syarat menjawab :
• terserah mau utamakan pertambahan atau perkalian .
• kalau absen saya kasih like
• koreksinya agak slowrespon

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

◐.̃◐Penyelesaian◐.̃◐

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Soal 1

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(1) = 2(1.1.1) + 2(1.1) - 2(1) × 2(1) - 5 × 2(1.1)

f(1) = 2(1) + 2(1) - 2(1) × 2(1) - 5 × 2(1)

f(1) = 2 + 2 - 2 × 2 - 5 × 2

f(1) = 2 + 2 - 4 - 5 × 2

f(1) = 2 + 2 - 4 - 10

f(1) = 4 - 4 - 10

f(1) = 0 - 10

f(1) = -10

Soal 2

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(2) = 2(2.2.2) + 2(2.2) - 2(2) × 2(2) - 5 × 2(2.2)

f(2) = 2(8) + 2(4) - 2(2) × 2(2) - 5 × 2(4)

f(2) = 16 + 8 - 4 × 4 - 5 × 8

f(2) = 16 + 8 - 16 - 5 × 8

f(2) = 16 + 8 - 16 - 40

f(2) = 24 - 16 - 40

f(2) = 8 - 40

f(2) = -32

Soal 3

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(3) = 2(3.3.3) + 2(3.3) - 2(3) × 2(3) - 5 × 2(3.3)

f(3) = 2(27) + 2(9) - 2(3) × 2(3) - 5 × 2(9)

f(3) = 54 + 18 - 6 × 6 - 5 × 18

f(3) = 54 + 18 - 36 - 90

f(3) = 72 - 36 - 90

f(3) = 36 - 90

f(3) = -54

Soal 4

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(4) = 2(4.4.4) + 2(4.4) - 2(4) × 2(4) - 5 × 2(4.4)

f(4) = 2(64) + 2(16) - 2(4) × 2(4) - 5 × 2(16)

f(4) = 128 + 32 - 8 × 8 - 5 × 32

f(4) = 128 + 32 - 64 - 160

f(4) = 160 - 64 - 160

f(4) = 96 - 160

f(4) = -64

Soal 5

f(x) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(5) = 2(5.5.5) + 2(5.5) - 2(5) × 2(5) - 5 × 2(5.5)

f(5) = 2(125) + 2(25) - 2(5) × 2(5) - 5 × 2(25)

f(5) = 250 + 50 - 10 × 10 - 5 × 50

f(5) = 250 + 50 - 100 - 250

f(5) = 300 - 100 - 250

f(5) = 200 - 250

f(5) = -50

Soal 6

f(6) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(6) = 2(6.6.6) + 2(6.6) - 2(6) × 2(6) - 5 × 2(6.6)

f(6) = 2(216) + 2(36) - 2(6) - 5 × 2(36)

f(6) = 432 + 72 - 12 - 360

f(6) = 504 - 12 - 360

f(6) = 492 - 360

f(6) = 132

Soal 7

f(7) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(7) = 2(7.7.7) + 2(7.7) - 2(7) × 2(7) - 5 × 2(7.7)

f(7) = 2(343) + 2(49) - 2(7) × 2(7) - 5 × 2(49)

f(7) = 686 + 98 - 14 × 14 - 5 × 98

f(7) = 686 + 98 - 192 - 490

f(7) = 784 - 192 - 490

f(7) = 592 - 490

f(7) = 102

Soal 8

f(8) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(8) = 2(8.8.8) + 2(8.8) - 2(8) × 2(8) - 5 × 2(8.8)

f(8) = 2(512) + 2(64) - 2(8) × 2(8) - 5 × 2(64)

f(8) = 1.024 + 128 - 16 × 16 - 5 × 128

f(8) = 1.024 + 128 - 256 - 640

f(8) = 1.152 - 256 - 640

f(8) = 896 - 640

f(8) = 256

Soal 9

f(9) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(9) = 2(9.9.9) + 2(9.9) - 2(9) × 2(9) - 5 × 2(9.9)

f(9) = 2(729) + 2(81) - 2(9) × 2(9) - 5 × 2(81)

f(9) = 1.458 + 162 - 18 × 18 - 5 × 162

f(9) = 1.458 + 162 - 324 - 810

f(9) = 1.620 - 324 - 810

f(9) = 1.296 - 810

f(9) = 486

Soal 10 (Bonus)

f(10) = 2x³ + 2x² - 2x × 2x - 5 × 2x²

f(10) = 2(10.10.10) + 2(10.10) - 2(10) × 2(10) - 5 × 2(10.10)

f(10) = 2(1.000) + 2(100) - 2(10) × 2(10) - 5 × 2(100)

f(10) = 2.000 + 200 - 20 × 20 - 5 × 200

f(10) = 2.000 + 200 - 400 - 1.000

f(10) = 2.200 - 400 - 1.000

f(10) = 1.800 - 1.000

f(10) = 800

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๛Detail Jawaban๛

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Last Update: Tue, 20 Sep 22