Penjelasan dengan langkah-langkah:

=> jawaban :

x - 2y + z = 6 (1) x 2

x - 2y + z = 6 (1) x 23x + y - 2z = 4 (2) x 1

x - 2y + z = 6 (1) x 23x + y - 2z = 4 (2) x 17x - 6y - z = 10 (3)

nilai x = 5, y = 3, dan z adalah 7

cara :

x - 2y + z = 6 l×2l 2x - 4y + 2z = 12

3x + y - 2z = 4 l1×1l 3x + y - 2z = 4

•••••••••••••••••••••• _____________ +

5x - 3y = 16

Eliminasi pers 1, pers 3

x +- 2y + z = 6

7x - 6y - z = 10

__________ +

8x - 8y = 16

x - y = 2 ... pers V

Eliminasi pers IV, pers V

5x - 3y = 16 l×1l 5× - 37 = 16

x - y = 2 l×3l 3x - 3y = 6

------------------------ -

2x = 10

x = 10/2

x = 5

subtitusi x = 5

x - y = 2

5 - y = 2

y = 5-2

y = 3

subtitusi x = 5 dan y = 3

x - 2y + z = 6

5 - 2 (4) + z = 6

5-6 + z = 6

-1 + z = 6

z = 6+1

z = 7

# koreksi

( maaf kalau kurang di pahami)