PENJELASAN

x3 - (a + b + c)x2 + (ab + ac + bc)x - abc = 0

x3 = 4x - 1

(4x - 1) - (a + b + c)(4x - 1)/4 + (ab + ac + bc)x - abc/4 = 0

(a + b + c)x2 - (ab + ac + bc)x + abc = 0

p = a + b + c

q = ab + ac + bc

r = abc

px^2 - qx + r = 0

a + b + c = p = 0

ab + ac + bc = q = -4/1 = -4

abc = r = -1/1 = -1

Rumus kuadratik :

x = [-(-4) ± √((-4)2 - 4(0)(-1))] / 2(0) = [4 ± 2√5] / 2 = 2 ± √5

maka :

a = 2 + √5

b = 2 - √5

c = -2

Jadi, nilai numerik dari a, b, dan c adalah a = 2 + √5, b = 2 - √5, dan c = -2.