Jawaban:

a. saya anggap di soal a tulisan n+1 nya di penyebut ya, lain kali dikasih [ ] biar lebih jelas itu di pembilang atau penyebut

p(n+1) = 5/[(n+1)(n+1+1)]

= 5/[(n+1)(n+2)]

=5/[n^2 + 3n + 2]

b. p(n+1) = 3/[(n+1)(n+1+2)(n+1+3)]

= 3/[(n+1)(n+3)(n+4)]

= 3/[(n^2+4n+3)(n+4)]

= 3/(n^3 + 4n^2 + 4n^2 + 16n + 3n + 12)

= 3/(n^3 + 8n^2 + 19n + 12)

c. p(n+1) = [(n+1)^2 (n+1-1)^2]/4

= [(n^2 + 2n + 1) n^2]/4

= (n^4 + 2n^3 + n^2)/4

d. p(n+1)=[(n+1)^2]/[2(n+1+1)^2]

= (n^2 + 2n + 1)/[2(n+2)^2]

= (n^2 + 2n + 1)/[2(n^2 + 4n + 4)]

= (n^2 + 2n + 1)/(2n^2 + 8n + 8)