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Diagram 3 shows a composite solid, formed by joining a

Berikut ini adalah pertanyaan dari lvtycrvt pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross - section of the right prism. MK is the diameter of the half - cylinderGiven BK 28 cm, AJ = 14 and AE = 20 cm, The volume of the composite solid is 17000 cm³

Using
\pi = \frac{22}{7}
calculate the value of h

pls help me answer this ​
Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross - section of the right prism. MK is the diameter of the half - cylinder Given BK 28 cm, AJ = 14 and AE = 20 cm, The volume of the composite solid is 17000 cm³ Using [tex]\pi = \frac{22}{7} [/tex]calculate the value of hpls help me answer this ​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

If you think about composite solid id 17000 cm³, it means that is a combined between half cylinder and trapezium prism. It means in math model:

Volume of half cylinder + volume trapezium prism = 17.000

1/2 π r² t + (\frac{(KB + JA) * BA}{2}) = 17.000

(Half in volume of half cylinder because that solid is really half not full cylinder)

1/2 * 3,14 * 10 * 10 * 28 + (\frac{(28 + 14) * h}{2}) = 17.000

(Remember 10 from where? 10 is from 20 that required as radius of a half circle)

(Use a 3,14 to make a solvable result)

1/2 * 314 * 28 + (\frac{42 * h}{2}) = 17.000

4396 + 21h = 17.000

21h = 17.000 - 4396

21h = 12604

h = 12604 : 21

h = 600,19 cm

So the value of h is 600,19 cm.

If you think about composite solid id 17000 cm³, it means that is a combined between half cylinder and trapezium prism. It means in math model:Volume of half cylinder + volume trapezium prism = 17.0001/2 π r² t + [tex](\frac{(KB + JA) * BA}{2})[/tex] = 17.000(Half in volume of half cylinder because that solid is really half not full cylinder)1/2 * 3,14 * 10 * 10 * 28 + [tex](\frac{(28 + 14) * h}{2})[/tex] = 17.000(Remember 10 from where? 10 is from 20 that required as radius of a half circle)(Use a 3,14 to make a solvable result)1/2 * 314 * 28 + [tex](\frac{42 * h}{2})[/tex] = 17.0004396 + 21h = 17.00021h = 17.000 - 439621h = 12604h = 12604 : 21h = 600,19 cmSo the value of h is 600,19 cm.

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Last Update: Tue, 11 Oct 22
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