Question : vba check if certain bits are set in longlong integer
Answered by : daniel-ferry
'Fast VBA function to test if specific bits are set
'within a 64-bit LongLong integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 63, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
'Note: the LongLong data type is only available in 64-bit VBA.
Function LongLongBitsAreSet(theLongLong^, ParamArray bits()) As Boolean Static i&, b^() If UBound(bits) = -1 Then Exit Function If (Not Not b) = 0 Then ReDim b(0 To 62) For i = 0 To 62 b(i) = 2 ^ i Next End If For i = 0 To UBound(bits) If bits(i) < 0 Then Exit Function If bits(i) > 62 Then Exit Function If (theLongLong And b(Int(bits(i)))) = 0 Then Exit Function Next LongLongBitsAreSet = True
End Function
'----------------------------------------------------------------------------------------------------------------------------------------------------------------------
MsgBox LongLongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11111111
MsgBox LongLongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11100110
MsgBox LongLongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 01010101
MsgBox LongLongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 01010101
MsgBox LongLongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000000 00000000 00000000 00000000 00000001 11100101
MsgBox LongLongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 00000000 00000000 00000000 00000000 01100000 00001001
MsgBox LongLongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 00000000 00000000 00000000 00000000 01111101 00010010 11101010 11001011
MsgBox LongLongBitsAreSet(2 ^ 62 + 1, 62, 0) '<--displays: True 4611686018427387905 = 01000000 00000000 00000000 00000000 00000000 00000000 00000000 00000001
'
'
'Source : http://academy.excelhero.com/ | Last Update : Sun, 14 Feb 21
Question : excel vba test if particular bits set in long integer
Answered by : daniel-ferry
'Fast VBA function to test if specific bits are set
'within a 32-bit Long integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
Function LongBitsAreSet(theLong&, ParamArray bits()) As Boolean Static i&, b&() If UBound(bits) = -1 Then Exit Function If (Not Not b) = 0 Then ReDim b(0 To 30) For i = 0 To 30 b(i) = 2 ^ i Next End If For i = 0 To UBound(bits) If bits(i) < 0 Then Exit Function If bits(i) > 30 Then Exit Function If (theLong And b(Int(bits(i)))) = 0 Then Exit Function Next LongBitsAreSet = True
End Function
'---------------------------------------------------------------------------------------------------------------------
MsgBox LongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 11111111
MsgBox LongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 11100110
MsgBox LongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000001 11100101
MsgBox LongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 01100000 00001001
MsgBox LongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 01111101 00010010 11101010 11001011
'
'
'Source : http://academy.excelhero.com/ | Last Update : Sun, 14 Feb 21
Question : excelvba check if bit set in 64-bit longlong integer
Answered by : daniel-ferry
'Extremely fast VBA function to test if a specified bit is set
'within a 64-bit LongLong integer.
'Bits are numbered from 0 to 63, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 63, the sign bit.
'Note: the LongLong data type is only available in 64-bit VBA.
Function LongLongBitIsSet(theLongLong^, bit As Byte) As Boolean Static i&, b^() If (Not Not b) = 0 Then ReDim b(0 To 62) For i = 0 To 62 b(i) = 2 ^ i Next End If If bit < 63 Then LongLongBitIsSet = theLongLong And b(bit)
End Function
'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7) '<--displays: True
MsgBox LongBitIsSet(230, 0) '<--displays: False
MsgBox LongBitIsSet(16384, 14) '<--displays: True
MsgBox LongBitIsSet(-16383, 0) '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0), 0) '<--displays: True
MsgBox LongLongBitIsSet(&H7FFFFFFFFFFFFFff^, 62) '<--displays: True
'
'
'Source : http://academy.excelhero.com/ | Last Update : Fri, 12 Feb 21