Random String

[Solved] Random String | Swift - Code Explorer | yomemimo.com
Question : Generate Random String

Answered by : excited-echidna-ab0c206me8wo

private static Random random = new Random();
public static string RandomString(int length)
{ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());
}

Source : https://stackoverflow.com/questions/1344221/how-can-i-generate-random-alphanumeric-strings | Last Update : Sun, 21 Jun 20

Question : Generate Random String

Answered by : combative-centipede-p67bb4ontliz

const randomString = Math.random().toString(36).slice(2);
console.log(randomString); //output- r0zf1xfqcr (the string will be random )

Source : https://dev.to/ikamran/7-killer-javascript-one-liners-that-you-must-know-2lla | Last Update : Mon, 31 Jan 22

Question : random string

Answered by : lype

// this one is quite compact and generates 11 random letters+numbers
Math.random().toString(36).substring(2) // random output like "0r4q9s1how7"
// just change substring() from 2 to 11 to reduce the string

Source : | Last Update : Thu, 10 Feb 22

Question : generate a random string

Answered by : robert-redd

{"tags":[{"tag":"textarea","content":"openssl rand -base64 12","code_language":"whatever"},{"tag":"p","content":"or"},{"tag":"p","content":"openssl rand -hex 12 "}]}

Source : https://unix.stackexchange.com/questions/230673/how-to-generate-a-random-string | Last Update : Thu, 23 Mar 23

Question : Random String

Answered by : prashant-priyadarshi

private static Random random = new Random();
public static string RandomString(int length)
{ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());
}

Source : https://stackoverflow.com/questions/1344221/how-can-i-generate-random-alphanumeric-strings | Last Update : Thu, 30 Dec 21

Question : Generate random string

Answered by : chinanu-prince

Math.random().toString(36).substring(2, 15) + Math.random().toString(36).substring(2, 15);

Source : | Last Update : Sun, 22 May 22

Question : random string generator algorithm

Answered by : omo-junior

<?php
declare(strict_types=1);
function randomStrGenerator(int $length): string
{ $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'; $randomString = ''; if ($length < 5) { return 'inputed value must be greater than 4'; } else { for ($i = 0; $i < $length; $i++) { $index = rand(0, strlen($characters) - 1); $randomString .= $characters[$index]; } return $randomString; }
}
echo "Error : ".randomStrGenerator(4)."\n"; //This will throw an error with what the function expects
echo "Length of 5: ".randomStrGenerator(5)."\n"; // This will give us a random length of 5 strings
echo "Length of 10: ".randomStrGenerator(10)."\n";//This will give us a random length of 10 strings
echo "Length of 20: ".randomStrGenerator(20)."\n";//This will give us a random length of 20 strings
echo "Hope you find this helpful";

Source : | Last Update : Mon, 21 Nov 22

Question : Generate Random String

Answered by : good-giraffe-nhn4idpiji4c

// Create a function for reusable perpose
const generateRandomString = (myLength) => { const chars = "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz1234567890"; const randomArray = Array.from( { length: myLength }, (v, k) => chars[Math.floor(Math.random() * chars.length)] ); const randomString = randomArray.join(""); return randomString;
};
// Try it
console.log(generateRandomString(10));
console.log(generateRandomString(30));

Source : https://www.kindacode.com/article/how-to-easily-generate-a-random-string-in-node-js/ | Last Update : Sun, 09 Oct 22

Question : random string

Answered by : grieving-grouse-is1gtfx4ee3r

{"tags":[{"tag":"textarea","content":"//Can change 7 to 2 for longer results.\nlet randomString = (Math.random() + 1).toString(36).substring(6);\n","code_language":"javascript"},{"tag":"p","content":"Create a random string 6-characters long.<br>"}]}

Source : https://stackoverflow.com/questions/1349404/generate-random-string-characters-in-javascript | Last Update : Tue, 28 Mar 23

Question : Random String

Answered by : tender-thrush-1gcyofbjdezv

string STRING = "Test 1\nTest 2\nTest 3\nTest 4\nTest 5";
int webLines = STRING.Split('\n').Length;
int lineNumber = UnityEngine.Random.Range(0, webLines - 1);
string lineText = STRING.Split('\n').ElementAtOrDefault(lineNumber);

Source : | Last Update : Sat, 28 May 22

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