def isPrime(n): if n<2:	#1, 0 and all negative numbers are not prime return False elif n==2:	#2 is prime but cannot be calculated with the formula below becuase of the range function return True else: for i in range(2, n): if (n % i) == 0:	#if you can precisely divide a number by another number, it is not prime return False return True	#if the progam dont return False and arrives here, it means it has checked all the numebrs smaller than n and nono of them divides n. So n is prime

def is_prime(n: int) -> bool: """Primality test using 6k+-1 optimization.""" import math if n <= 3: return n > 1 if n % 2 == 0 or n % 3 == 0: return False i = 5 while i <= math.sqrt(n): if n % i == 0 or n % (i + 2) == 0: return False i += 6 return True

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