Question : java random uuid
Answered by : paul-smith-h1kxhourr6fx
String id = UUID.randomUUID().toString();
Source : | Last Update : Thu, 04 Mar 21
Question : java generate uuid
Answered by : lively-lyrebird-qlrlmd0osg81
public static void main(String[] args) { final String uuid = UUID.randomUUID().toString().replace("-", ""); System.out.println("uuid = " + uuid);
}
Source : https://stackoverflow.com/questions/3804591/efficient-method-to-generate-uuid-string-in-java-uuid-randomuuid-tostring-w | Last Update : Mon, 06 Jun 22
Question : java random uuid
Answered by : comfortable-caiman-tqkrvwuy2a0x
import java.security.SecureRandom;
import java.util.UUID;
public class RandomUtil { // Maxim: Copied from UUID implementation :) private static volatile SecureRandom numberGenerator = null; private static final long MSB = 0x8000000000000000L; public static String unique() { SecureRandom ng = numberGenerator; if (ng == null) { numberGenerator = ng = new SecureRandom(); } return Long.toHexString(MSB | ng.nextLong()) + Long.toHexString(MSB | ng.nextLong()); }
}
Source : https://coders911.org/questions/3804591/Efficient-method-to-generate-UUID-String-in-JAVA-UUIDrandomUUIDtoString-without-the-dashes | Last Update : Sun, 10 Apr 22
Question : grepper subscription required
Answered by : code-grepper
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Source : | Last Update : Mon, 27 Mar 23
Question : java random uuid generating
Answered by : taha-dnk
import java.util.UUID;
public class RandomUUIDGenerator { public static void main(String[] args) { // Generate a random UUID UUID randomUUID = UUID.randomUUID(); // Convert UUID to String String uuidString = randomUUID.toString(); // Print the generated UUID System.out.println("Random UUID: " + uuidString); }
}
Source : https://chat.openai.com/c/b1e007ba-d21a-4372-8782-61278a5496f7 | Last Update : Fri, 05 Jan 24